$(\frac{{97}^3-{53}^3}{44}+97\ast 53):(152,5^2-27,5^2)=(\frac{(97-53)({97}^2+97\ast 53+{53}^2)}{44}+97\ast 53):((152,5-27,5)(152,5+27,5))=(\frac{44\ast ({97}^2+97\ast 53+{53}^2)}{44}+97\ast 53):(125\ast 180)=({97}^2+97\ast 53+{53}^2+97\ast 53):(125\ast 180)=({97}^2+2\ast 97\ast 53+{53}^2):(125\ast 180)=(97+53{)}^2:(125\ast 180)=\frac{{150}^2}{125\ast 180}=\frac{150\ast 150}{125\ast 180}=\frac{6\ast 5}{5\ast 6}=1$

$(36,5^2-27,5^2):(\frac{{57}^3+{33}^3}{90}-57\ast 33)=((36,5-27,5)(36,5+27,5)):(\frac{(57+33)({57}^2-57\ast 33+{33}^2)}{90}-57\ast 33)=(9\ast 64):(\frac{90\ast ({57}^2-57\ast 33+{33}^2)}{90}-57\ast 33)=(9\ast 64):({57}^2-57\ast 33+{33}^2-57\ast 33)=(9\ast 64):({57}^2-2\ast 57\ast 33+{33}^2)=\frac{9\ast 64}{(57-33{)}^2}=\frac{9\ast 64}{{24}^2}=\frac{9\ast 64}{24\ast 24}=\frac{1\ast 64}{8\ast 8}=1$

$(\frac{{79}^3-{41}^3}{38}+79\ast 41):(133,5^2-58,5^2)=(\frac{(79-41)({79}^2+79\ast 41+{41}^2)}{38}+79\ast 41):((133,5-58,5)(133,5+58,5))=(\frac{38\ast ({79}^2+79\ast 41+{41}^2)}{38}+79\ast 41):(75\ast 192)=({79}^2+79\ast 41+{41}^2+79\ast 41):(75\ast 192)=\frac{{79}^2+2\ast 79\ast 41+{41}^2}{75\ast 192}=\frac{(79+41{)}^2}{75\ast 192}=\frac{{120}^2}{75\ast 192}=\frac{120\ast 120}{75\ast 192}=\frac{8\ast 5}{5\ast 8}=1$

$(94,5^2-30,5^2):(\frac{{69}^3+{29}^3}{98}-69\ast 29)=((94,5-30,5)(94,5+30,5)):(\frac{(69+29)({69}^2-69\ast 29+{29}^2)}{98}-69\ast 29)=(64\ast 125):(\frac{98\ast ({69}^2-69\ast 29+{29}^2)}{98}-69\ast 29)=(64\ast 125):({69}^2-69\ast 29+{29}^2-69\ast 29)=\frac{64\ast 125}{{69}^2-2\ast 69\ast 29+{29}^2}=\frac{64\ast 125}{(69-29{)}^2}=\frac{64\ast 125}{{40}^2}=\frac{64\ast 125}{40\ast 40}=\frac{1\ast 125}{5\ast 5}=5$